在F＃中创建复合迭代器
我正在实现类似跳棋的游戏，我需要一个列举给定配置的所有合法移动的序列。
我有以下函数，直接从C＃翻译：
seq {
for y1 = 0 to BOARDSIZE-1 do
for x1 = 0 to BOARDSIZE-1 do
for dy = -2 to 2 do
for dx = -2 to 2 do
let x2 = x1 + dx;
let y2 = y1 + dy;
let currentMove = new MoveStruct(x1, y1, x2, y2);
if (currentMove.SomeCondition = true) then
yield currentMove;
}
let AllCells =
seq {
for y=0 to BOARDSIZE-1 do
for x=0 to BOARDSIZE-1 do
yield (x,y);
};
let LegalMovesAround(x1,y1) =
seq {
if board.[x1, y1] = WHITE then
for dy = -2 to 2 do
for dx = -2 to 2 do
let x2 = x1 + dx;
let y2 = y1 + dy;
let currentMove = new MoveStruct(x1, y1, x2, y2);
if (currentMove.DetermineMoveType <> MoveType.ILLEGAL
&& board.[x2, y2] = NONE) then
yield currentMove;
}
没有找到相关结果
已邀请:
3 个回复
掀辟髓观粟
let validMoves = AllCells |> Seq.collect LegalMovesAround |> Seq.distinct嗓瑰
let allLegalMoves = seq { for cell in AllCells do yield! LegalMovesAround cell }伞腹
？ 就像是seq { for x,y in Allcells do yield! LMA(x,y) }