如何计算阵列单元阵列的加权平均值？
在我之前的问题的概括中，如何对单元格元素（即并且将保留数组本身）的加权平均值执行？
我首先修改gnovice的答案，如下所示：
dim = ndims(c{1}); %# Get the number of dimensions for your arrays
M = cat(dim+1,c{:}); %# Convert to a (dim+1)-dimensional matrix
meanArray = sum(M.*weigth,dim+1)./sum(weigth,dim+1); %# Get the weighted mean across arrays
weight
M.*weight
c = { [1 2 3; 1 2 3], [4 8 3; 4 2 6] };
weight = [ 2, 1 ];
meanArray = [ 2 4 3; 2 2 4 ]
没有找到相关结果
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屠创氓读叔
function meanArray = cellMean(c, weight) % meanArray = cellMean(c, [weight=1]) % mean over the elements of a cell c, keeping matrix structures of cell % elements etc. Use weight if given. % based on http://stackoverflow.com/q/5197692/321973, courtesy of gnovice % (http://stackoverflow.com/users/52738/gnovice) % extended to weighted averaging by Tobias Kienzler % (see also http://stackoverflow.com/q/5231406/321973) dim = ndims(c{1}); %# Get the number of dimensions for your arrays if ~exist('weight', 'var') || isempty(weight); weight = 1; end; eins = ones(size(c{1})); % that is german for "one", creative, I know... if ~iscell(weight) % ignore length if all elements are equal, this is case 1 if isequal(weight./max(weight(:)), ones(size(weight))) weight = repmat(eins, [size(eins)>0 length(c)]); elseif isequal(numel(weight), length(c)) % case 2: per cell-array weigth weight = repmat(shiftdim(weight, -3), [size(eins) 1]); else error(['Weird weight dimensions: ' num2str(size(weight))]); end else % case 3, insert some dimension check here if you want weight = cat(dim+1,weight{:}); end; M = cat(dim+1,c{:}); %# Convert to a (dim+1)-dimensional matrix sumc = sum(M.*weight,dim+1); sumw = sum(weight,dim+1); meanArray = sumc./sumw; %# Get the weighted mean across arrays