每个城市十个最便宜的房间
|
我有3张桌子的房间,酒店,城市,我该如何选择每个城市的十个最便宜的房间及其hotel_id
可以为每个城市执行子查询?
SELECT price, room_id, hotel_id, city_id
FROM Hotel
JOIN Room USING(hotel_id)
ORDER BY price
LIMIT 10
Scheme
CREATE TABLE `City` (
`city_id` int(11) NOT NULL AUTO_INCREMENT,
`city_name` varchar(50) NOT NULL,
PRIMARY KEY (`city_id`)
)
CREATE TABLE `Hotel` (
`hotel_id` int(11) NOT NULL AUTO_INCREMENT,
`city_id` int(11) NOT NULL,
`hotel_name` varchar(100) NOT NULL,
PRIMARY KEY (`hotel_id`),
CONSTRAINT `Hotel_FK_1` FOREIGN KEY (`city_id`) REFERENCES `City` (`city_id`) ON DELETE CASCADE ON UPDATE CASCADE
)
CREATE TABLE `Room` (
`room_id` int(11) NOT NULL AUTO_INCREMENT,
`hotel_id` int(11) NOT NULL,
`room_name` varchar(255) DEFAULT NULL,
`room_price1` int(11) DEFAULT NULL,
PRIMARY KEY (`room_id`),
CONSTRAINT `Room_FK_1` FOREIGN KEY (`hotel_id`) REFERENCES `Hotel` (`hotel_id`) ON DELETE CASCADE ON UPDATE CASCADE
)
用子查询查询
SELECT
r.room_price1, r.room_id, h.hotel_name, c.city_name
FROM Hotel h
INNER JOIN Room r ON
h.hotel_id = r.hotel_id
INNER JOIN City c USING(city_id)
WHERE (
SELECT count(*) from Room as rt
JOIN Hotel ht using(hotel_id)
where c.city_id = ht.city_id and rt.room_price1 < r.room_price1 OR (rt.room_price1 = r.room_price1 AND rt.room_id < r.room_id)
) < 3
ORDER BY c.city_name, h.hotel_id, r.room_price1
如果某些酒店有一些room_price1,则此查询返回多于3行的城市信息,并且我需要每个城市3个唯一的酒店,此查询可以从一个酒店返回3个房间
请尝试使用用户变量
set @num := 0, @type := \'\';
select *
from (
select r.room_price1 pr, r.room_id, h.hotel_name, c.city_name,
@num := if(@type = city_id, @num + 1, 1) as row_number,
@type := city_id as dummy
from Hotel h
JOIN Room r USING(hotel_id)
INNER JOIN City c USING(city_id)
order by city_name, r.room_price1 asc
) as x where x.row_number <=3;
对于row_number <6(我的初始化数据),此方法返回错误的排序
没有找到相关结果
已邀请:
2 个回复
仿普
让我们尝试一下
如您所见,您可以进行子查询以选择所有房间的数量 价格低于当前根的价格,看看是否 计数小于或等于10。 特别要注意我如何改变
至
因为在Xaprb的示例中,他选择了N个最便宜的水果 希望能有所帮助。 BTW Stackoverflow并非用于解决作业。您也应该学习一些自己的东西;-)
坝镰补翔奋