使用std :: cout时如何模拟printf的％p格式？

unsigned char *teta = ....;
...
printf(\"data at %p\\n\", teta); // prints 0xXXXXXXXX

iostream

std::hex

std::cout << std::??? << teta << std::endl

unsigned char* teta = ....;
std::cout << \"data at \" << static_cast<void*>(teta) << \"\\n\";

char*

void*

std::cout

unsigned char *teta = ....;
...
char formatted[ 256 ]; //Caution with the length, there is risk of a buffer overflow
sprintf( formatted, \"data at %p\\n\", teta );
std::cout << formatted;