获取数组的索引，并删除该索引剩下的所有内容
|
我有一个
int
int[] RowOfints = 1,2,3,4,5,6,7,8,9;
4
1,2,3
没有找到相关结果
已邀请:
6 个回复
疾很毋悲
的索引，然后从该索引位置开始的所有内容的问题。将是由组成的。如果需要一个具体的数组，也可以使用可选的扩展方法。如果数组中没有元素符合给定条件，则将得到一个零长度的序列。坍锭嘉韭蓝
磋判粗惊
祁澈盘哼颗
private static int[] RemoveBeforeValue(int[] source, int value) { if (source == null) return null; int valueIndex = 0; while (valueIndex < source.Length && source[valueIndex] != value) valueIndex++; if (valueIndex == 0) return source; int[] result = new int[source.Length - valueIndex]; Array.Copy(source, valueIndex, result, 0, result.Length); return result; }private static int[] RemoveValuesLessThan(int[] source, int newMinimum) { if (source == null) return null; int lessThanCount = 0; for (int index = 0; index < source.Length; index++) if (source[index] < newMinimum) lessThanCount++; if (lessThanCount == 0) return source; int[] result = new int[source.Length - lessThanCount]; int targetIndex = 0; for (int index = 0; index < source.Length; index++) if (source[index] >= newMinimum) result[targetIndex++] = source[index]; return result; }链眷克袒姜
public static void RemoveIntsBefore(int i) { int[] RowOfints = { 1, 2, 3, 4, 5, 6, 7, 8, 9 }; for (int k = 0; k < RowOfints.Length; k++) { if (RowOfints.ElementAt(k) < i) { RowOfints[k] = i; } } RowOfints = RowOfints.Distinct().ToArray(); //this part is to write it on console //foreach (var item in RowOfints) //{ // Console.WriteLine(item); //} //Console.ReadLine(); }public static void RemoveIntsBefore(int i) { int[] RowOfints = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 1,2 }; Console.WriteLine(\"OUTPUT\"); foreach (var item in Enumerable.Range(i-1, RowOfints.Length + 1 - i).ToArray()) { Console.WriteLine(RowOfints[item]); } Console.ReadLine(); }视蕉梁拌客
int[] RowOfints = {1,2,3,4,5,6,7,8,9}; int[] Answer = RowOfints.Where(x => x != 1 && x != 2 && x != 3).ToArray()