仿真中的无限循环
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我从python开始。.我在下面编写的详细信息..它进入无限循环，当我尝试在内部调用该函数时给我一个错误。.是否不允许这种递归？
在下面发布代码。.感谢您的所有帮助:)
该计划假设我们有100名乘客登机。假设第一个人失去了登机牌，他会找到一个随机的座位并坐在那里。然后，如果没有人坐下，其他来客将坐在他们的位置，如果有人坐下，则坐在其他随机座位上。
最终目的是找到最后一位乘客不会坐在自己座位上的可能性。我还没有添加循环部分
使其成为适当的模拟。上面的问题实际上是概率上的难题。我尝试验证答案，因为我没有真正遵循推理。
import random
from numpy import zeros
rand = zeros((100,3))
# The rows are : Passenger number , The seat he is occupying and if his designated seat is occupied. I am assuming that the passengers have seats which are same as the order in which they enter. so the 1st passenger enter has a designated seat number 1, 2nd to enter has no. 2 etc.
def cio(r): # Says if the seat is occupied ( 1 if occupied, 0 if not)
if rand[r][2]==1:
return 1
if rand[r][2]==0:
return 0
def assign(ini,mov): # The first is passenger no. and the second is the final seat he gets. So I keep on chaning the mov variable if the seat that he randomly picked was occupied too.
if cio(rand[mov][2])== 0 :
rand[mov][2] = 1
rand[mov][1] = ini
elif cio(rand[mov][2])== 1 :
mov2 = random.randint(0,99)
# print(mov2) Was used to debug.. didn\'t really help
assign(ini,mov2) # I get the error pointing to this line :(
# Defining the first passenger\'s stats.
rand[0][0] = 1
rand[0][1] = random.randint(1,100)
m = rand[0][1]
rand[m][2]= 1
for x in range(99):
rand[x+1][0] = x + 2
for x in range(99):
assign(x+1,x+1)
if rand[99][0]==rand[99][1] :
print(1);
else :
print(0);
def assign(ini,mov):
if cio(mov)== 0 : \"\"\"Changed here\"\"\"
rand[mov][2] = 1
rand[mov][1] = ini
elif cio(mov)== 1 : \"\"\"And here\"\"\"
mov2 = random.randint(0,99)
assign(ini,mov2)
没有找到相关结果
已邀请:
2 个回复
课刊灭似
循环。def assign(ini,mov): \"\"\"The first is passenger no. and the second is the final seat he gets. So I keep on chaning the mov variable if the seat that he randomly picked was occupied too. \"\"\" while cio(rand[mov][2])== 1: mov = random.randint(0,99) assert cio(rand[mov][2])== 0 rand[mov][2] = 1 rand[mov][1] = ini之后的三引号字符串。墩瓣茅械